Python inspect get function name. One possible solution is a … # Public Domain, i.

Python inspect get function name For example, given a function def my_function(): pass, we want to retrieve the string "my_function". Hot Network Questions However, the inspect module seems to make a distinction between **kwarg and something called "keyword only arguments". – Sergei Lebedev In this example, sys. Here’s an example: import inspect isfunction (): This method returns true if the given argument is an inbuilt function name. Is there a way to get the current function I'm in? I'm looking for the actual function object, not the function name. In any case, I strongly recommend that you import the inspect code into some python code of your own, and look at what it can provide you -- Especially if you can single step through your code in a good python debugger. I want to be able to tell the two functions apart based on the information from inspect. __name__ the_method = stack[1][0 Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Visit the blog Overview of Python Get Function Name. How can this be achieved? Solutions Solution 1: Using the Inspect Module. args is a list of the parameter names. A named tuple is returned: FullArgSpec(args, varargs, varkw, defaults, kwonlyargs, kwonlydefaults, annotations) Modules¶. Then the code is an example of Get information about the arguments accepted by a code object. How can I get a variable that contains the currently executing function in Python? I don't want the function's name. __annotations__. co_name retrieves the name of the function that called B. f_code. getargspec(f)[0] def get_function_name(): frame = inspect. stack() the_class = stack[1][0]. co_name). 2. I know I can use inspect. This code imports the inspect module and defines a function get_function_name () that returns the name As shown, the __name__ attribute returns the name of the function as a string. I'm trying to use inspect. Method 1: Using the function. co_name. function print(get_function_name()) # Output: get_function_name Finally, we call the function and print the result, which will be “get_function_name”. Method 2: Utilizing the inspect Module. To get the filename of the caller, you need to use the sys. It appears that lambdas are the more complicated edge case function definitions with def are easier. For now, I got two ways to fetch the name of the current function/method in python. wraps function, which is designed to "update a wrapper function to look like the wrapped function". __code__. This knowledge can be particularly useful for debugging or Method 1: Use the __name__ Property to Get the Function Name in Python Method 2: Using the inspect Module Method 3: Using sys. Method 1: Using the sys Module Python Inspect and Functions. Getting function parameters from function name in python. We only need FrameInfo for current frame and immediate outer frame stacks = inspect. The challenge is to set caller_name to the __name__ attribute of the calling function’s module — in this case, myapp. "some_argument_name" - corresponds to an argument with a default value. One possible solution is a # Public Domain, i. stack to retrieve the function's name and then evaling the name to get the callable object? Use the inspect module from Python's standard library (the cleanest, most solid way to perform introspection). __class__. Here’s how you can do it: Passing arguments to functions in Python using inspect. return_annotation. getcallargs (func, *positional, **named) In [1]: import inspect In [2]: def test(): : print inspect. So in the case above it would be bar but if any other module imported foo I would like foo to dynamically have access to the name of that module. IPython), using different libraries (e. How to @pass_func_name def sum(a, b, _func_name): print "running function %s" % _func_name return a + b print sum(2, 4) But maybe you'd want to write what you want directly inside the decorator itself. _getframe() Method 4: Using I'm surprised that this question is so old and no one has taken the time to add the actual introspective way to do this, so here it is: The code you want to inspect import inspect def first(): return second() def second(): return inspect. This is obvious, because the code is located in the debugutil. Applied to the example from the question, the code would look like: This is because Python wraps the argument in a special ForwardRef class: d = signature. As Python is an OOP language and all the code that is written is basically an interaction between these objects, hence the inspect module becomes very useful in inspecting certain modules or certain objects. from a file versus interactively defined). Follow edited Jun 23, 2016 at 17:10 How to get a function name as a string? 1290. Learn how to get the name of a function as a string in Python with multiple code examples and explanations. Python’s get function name is a valuable tool for developers looking to retrieve the name of a function within their code. It can be used to examine code at runtime, to retrieve information about objects in a running program, and to enable dynamic analysis and debugging. if the coroutine is nested, it will get you the full path to your function. Python’s ‘inspect’ module is a powerful tool for debugging and understanding code. For example, it can help you examine the contents of a class, retrieve the source code of a method, extract and format the argument list for a function, or get all the information you need to Method 2: Using the inspect Module. parameters in the decorator and use logic to get the argument values in fn's wrapper, def wrapper(*args, **kwargs): , which is returned by the decorator. In this example, below code defines a function, `get_var_name`, which uses the inspect module to obtain the name of a variable given its value. f_back to find the caller's frame. It's easy to get the (unqualified) name and a code object for the currently executing function. >>> import os >>> import types >>> import Top 4 Methods to Retrieve the Caller Function Name in Python. ; Some prior answers use sys. ''' return logging. The inspect. _getframe which is an internal private function given its leading underscore, and so its use is implicitly discouraged. If you look at the Python C API, you'll see that the actual way arguments are passed to a normal Python function is always as a tuple plus a dict -- i. This will give you the fully qualified name, i. One way to access a function’s name in Explanation: inspect. f_back. getframeinfo() or inspect. [Python] Get nodeid, module, function name using Pytest request built-in fixture; How to get current file path in Python; How to generate a random number in python using random module; Python Measure the execution time of small bits of Python code with the timeit module [Python] Two ways to import a module; Column name as alias name SQLAlchemy You are always looking at a function context; the method context is already gone by the time the function executes. From the docs: inspect. __name__ = 'foo' Note that Python cannot know that you assigned the lambda function object to a specific name; the assignment takes place after the lambda expression was python . A named tuple is returned: FullArgSpec(args, varargs, varkw, defaults, kwonlyargs, kwonlydefaults, annotations) args is a list of the positional parameter names. e. __name__ returns a string. python ref, inspect. co_name) or to get the caller's name: print(inspect. get name of function passed as argument to parent function. (In many languages, a variable is more like a name for a specific location in memory where the value will be stored. 1. def _caller_param_name(pos): #The parameter name to return param = None #Get the frame object for this function call thisframe = inspect. stack()[1][3]) is the function name. So first of all you can get the function name using the __qualname__ attribute. 12, your results might very if you are running a different version. That's because I need to specify a different file name each time I'm running python 2. currentframe(). This attribute is built-in to every function object and provides a simple way to retrieve its name. Let’s delve deep into some effective ways to retrieve parameter names directly from your function definitions. _getframe(1) fetches the previous stack frame. Therefore, given a python 3 decorator function def decorate(fn): , you would simply do fn_params = inspect. Improve this question. . Method 2: Employing the inspect Module. Check out How to Use Default Function Arguments in Python?. getframeinfo to I'm running a python program (Python 2. _getframe(1)) Based on this answer by jsbueno, I found a solution for recovering the signature. parameters['a']. The fourth element of the frame record (inspect. py file. stack I can get the call stack:"['func(x)\n']", Getting function parameters from function name in python. currentframe(). python get parameters of passed function. The f_code. PyTorch) No, there is no way to do it in Python code with this signature -- if you need this information, you need to change the function's signature. Use importlib to import a module using a path and then use types module to filter out functions from that imported module. @JDOaktown a decorator function/class takes a function/class as its argument. getLogger (caller_name (skip + 1)) def caller_name (skip = 2): """Get a name of a caller in the format module. getouterframes( inspect. args is a list of the argument names (it may contain nested lists). argv[0] to get the script filename. currentframe() combined with function. co_name return current_function_name print(my_function()) # Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Is it possible do something like below where a new function get_name_doc would access the function from the outer frame from which it is called, and return its name and doc? def get_name_doc(): ??? #!/usr/bin/env python from inspect import (getframeinfo, currentframe, getouterframes) class classSelfDoc(object): @property def frameName(self This page has become a hot mess. I've come up with the following solution which gets the name, then looks it up in the calling You could print sys. def decoratorFunctionWithArguments(msg): def wrap(f): def wrapped_f(*args, **kwargs): print return f(*args, **kwargs) return wrapped_f return wrap I want to print out the following attributes of the function f: Name of the function; Name of the module this function was called. getsourcefile(sys, sys. /get_func_args. function # Get I want to write a function which returns the calling function: def foo(): return get_calling_function() #should return 'foo' function object There's numerous examples online how to get the calling function's name, but not how to get the actual object. parameters returns an ordered mapping of parameter names and extracting . Python3 When you need to get a list of parameter names inside a Python function, you might wonder about the best methods to achieve this. settrace. 3 introduced the __qualname__ attribute for function objects and class objects. getargspec(func) Get the names and default values of a Python function’s arguments. Function based >>> import inspect >>> import sys >>> def hello(): What I would like to be access inside the foo module is the name of the current executing module that is using foo. So this is how your remote function would look like To get the name of a function when using Python, you can use the __name__ property. This functionality can be achieved through two main methods: using the __name__ attribute and utilizing the inspect module. stack but it's known to be too slow. currentframe() )[1] first()[3] # 'first' Python Get function parent attribute. It is possible to probe live objects to determine their components using getmembers(). Technically speaking, functions act as descriptors when accessed as attributes on an instance (instance. programcreek, usage of inspect. (In some languages, this is not the case; although there The best way to get the caller of a Python function in a program is to use a debugger. I'd like to see this page evolve into a resource that can be read quickly to get a set of useful answers across different Python interactive environments (e. class. getframeinfo(frame). Hot Network Questions As shown, the __name__ attribute returns the name of the function as a string. You can use functions in this module to retrieve the original source code for a function, Lambdas are anonymous, which means they do not have a name. signature(fun). ismodule(objectName) True if the object is a Python module: inspect. Python’s inspect module provides a comprehensive way to access various attributes of live objects, including functions. 9. method `skip Well, after some digging at the prompt, here's what I get: stack = inspect. Method 4: Get Function Name in Python using the inspect module. input', the module name returned from get_verbose_prefix is still just 'input', not 'myproject. Example: Output: ismethod (): This method is used to check if the argument passed is By leveraging the __name__ attribute or the inspect module, we can easily determine the function name from within itself in Python 3. getargspec (func) Get the names and default values of a Python function’s parameters. foo. It's behaviour depends on Python version, however, as shown below. The return tuple is (name, suffix, mode, module_type), where name is the name of the module without the name of any enclosing package, suffix is the trailing part of the file name My issue is: When I have a module in a package, for instance 'myproject. utilities. How to get Python Object Parent? 2. varargs and keywords are the names of the * and ** parameters or None. , the way that's a direct reflection of a signature of *args, **kwargs. def foo(x,y): foo_again = <GET_CURRENT_FUNCTION> if foo_again == foo: print ("YES they are equal!") I assume I could do that in Python inspect module, but I can't seem to find it. Can this be done without using inspect. Home; Technology; Gaming; Below shows you how to get the name of the function you are currently in in This is solved with Python's standard library functools and specifically functools. varargs and keywords are the names of the * and ** arguments or None. Let’s delve into four distinct approaches that leverage built-in Python modules like sys and inspect, along with logging techniques. getargspec (func) Get the names and default values of a function’s arguments. I need to find out if the function exists -before- I do any of the prerequisite calculations needed to run it if it does exist. , give a name to) values. g. currentframe() to get the current frame and then I would use inspect. In Python, you can access the name of a function as a string using the __name__ attribute. inspect. I want the actual callable object. Function calls in Python can be nested, creating a need to identify the caller function from within a callee function. Here are the top four methods to accomplish this in Python. stack()[1] is the frame record of the function that calls whoami, like foo() and bar(). method_name), which return a method object. __forward_arg__ # 'User' Take note, you don't need to actually use inspect here, typing has a helper function named get_type_hints that returns the type hints as a dictionary (it uses the function objects __annotations__ Get the names and default values of a Python function's parameters. How get names of passed parameters inside a function. myfunc_l = lambda: None myfunc_l. annotation <class 'int'> The same can be achieved by doing f. Specifically, inspect. When you import a module, or run a top-level script, the first stage is compilation (unless there's already a cached . Get current function name from inside that function using Python. output: You could also use: print(inspect. CO_VARARGS. But Python's names actually name the thing in question. You can utilize Python’s powerful inspect module to get the information about the current execution context. 7. Method 1: Using locals() The built-in locals() function can be leveraged to get the local variable names, including the function’s parameters. ) In Python, a function is a value. Using a simple function, we can visualize how to access its name dynamically: print("my name is", __myname__) # How can we achieve this at runtime? foo() The expected With the python module inspect, one can inspect (not kidding) the run-time python stack. getfullargspec() inspect. Its use hasn't been covered in any of the prior answers which are mainly of one of three types: Some prior answers use inspect. 3. currentframe() return inspect. realpython, primer on python decorators capturing args kwargs. signature(f). With ‘inspect’, you can get information about functions and classes, inspect the source code, access variables and frames, and work with tracebacks. Using __name__. For more complex requirements, the inspect module can be utilized: Explore multiple methods to extract a function's name as a string in Python with practical examples and alternative techniques. Get variable from a parent function. getargspec(f) returns the names and default values of f's arguments -- if you only want the names and don't care about special forms *a, **k, import inspect def magical_way(f): return inspect. @cglacet I am looking for a generic solution working on any kind of function definition / function pointer / function reference. Edit: The inspect module looks quite promising but it is not exactly what I was If you want to understand why this works, you have to understand the stages here. But how to get the qualified name for the currently executing function? Introduction. getouterframes It prints out the file name and line number on which I defined the function, instead of the line on which I call debuginfo(). currentframe() function retrieves the current Python 3. You can use inspect. The method object then, when called, in turn calls the original function with the instance The caller's frame is one frame higher than the current frame. 5) that calls functions dynamically using the eval method. How do I get a list of locally installed Python modules? The inspect module provides several useful functions to help get information about live objects such as modules, classes, methods, functions, tracebacks, frame objects, and code objects. How can I get name of class including full path from its module root? python; inspect; Share. We can use inspect. getsource(my_function) function_name The inspect() method is a built-in Python function that provides information about live objects such as modules, classes, functions, and methods. varargs is the name of the * parameter or None if arbitrary positional arguments are not accepted. The inspect module helps in checking the objects present in the code that we have written. The inspect module in Python provides several useful functions to get information about live objects, including functions. If I have a reference to a "real" Python function inside a list for instance, similar to my example above with baz[2], inspect will indeed If you want to understand why this works, you have to understand the stages here. getblock (lines) Extract the block of code at the top of the given list of lines. stack to get the current function name. Then use inspect. feel free to copy/paste # Considered a hack in Python 2 import inspect import logging import sys def _L (skip = 0): '''Shorthand to get logger for current function frame. isfunction(foo). 0. It provides a comprehensive view of the function’s arguments but is Function Output; inspect. keys() converts them into a list. Use inspect. If a method is a class method, the class will be the first argument. _getframe() function to get the calling frame, then you can retrieve the filename from that: import inspect, sys print inspect. How to Get a Function Name as a String in Python. getfullargspec() retrieves a function’s parameter names along with details like default values and annotations. stack() # Get my_func's name (str) from current frame this_func_name = stacks[0]. The arguments to getmembers() are an object to scan (a module, class, or instance) and an optional predicate function that Using a python decorator as follows. For example: >>> import inspect >>> inspect. import inspect def my_function (): pass source_code = inspect. stack() function will return the call stack Let’s delve deep into some effective ways to retrieve parameter names directly from your function definitions. I can get the function name (not helpful) and I can get the Python is a dynamic language, so the only way to get the inner functions is to run the parent function (f2 in your example) and inspect the local variables using e. Use the inspect Module. Method 1: Using locals(). currentframe() try: #Get the parent calling frames details frames = inspect. isclass(objectName) True if the object is a Python class: inspect. getargvalues (frame) Get information about arguments passed into a particular frame. Print parameters passed to the function. stackoverflow, showing function name and param name/value pairs. Reference Links: Python 3 – inspect module documentation; Stack Overflow – How can I get a In function whoami(): inspect. __name__ Attribute. Getting information about functions and I'm looking for a way to check the number of arguments that a given function takes in Python. , for debugging or logging purposes). With the code-object provided by the frame's f_code you can use this function to find the frames itselve as well es the function. ismethod(objectName) True if the object is a Python bound Python uses names in the source code to refer to (i. getfullargspec(func) Get the names and default values of a Python function’s arguments. Among other things, this makes it possible to get the name of the current function or To get the function name, you can use inspect. f_code. pyc file). stack()[0][3] or, if you want to move it into a separate function, inspect. getmoduleinfo (path) ¶ Return a tuple of values that describe how Python will interpret the file identified by path if it is a module, or None if it would not be identified as a module. __parameter__[0] d. In Python, understanding how to retrieve the current function name can be beneficial for debugging, logging, and monitoring program flow. Return all the members of an object in a list of (name, value) pairs sorted by name without triggering dynamic lookup via the descriptor protocol, __getattr__ or __getattribute__. This prints out the type of the first arg if present for each calling stack frame: The inspect module is very powerful, and can be used in a similar fashion to the way you use traceback to get the name of the function, and probably also the class name. stack()[1][3]) # will give the caller of foos name, if something called foo. This method utilizes the built-in attribute __name__ available This approach directly accesses the function name, making it efficient and simple. This drastically reduces the helpfulness of the prefix in large projects when there can be several 'input' modules in different submodules all working together. The inspect module is a built-in Python module that provides a variety of functions for inspecting When inspecting at runtime the annotations of a function, one can get the class annotated for a given argument. To do this, I've been trying to employ the inspect python library, which uses inspect. markmiyashita, basic explanation of *args and **kwargs. We can also use it to get a detailed analysis of certain function calls 💡 Problem Formulation: In Python programming, there might be instances where we need to fetch a function’s name (e. Here's a proof of concept (beware the code to sort the arguments and match them to their defaults can definitely be improved/made more clear): It is possible to grab an object attribute using either getattr(obj, attr) or inspect. You can always assign a name to __name__ if you feel they should have one anyway:. saltycrane, var args. py Function Name my_func Function Name my_func_in_class args1: a: 1 b: 2 c: None args2 a: 10 b: 20 c: 30 (a, b, c=None): # Get Stacks. Find out which method is most reliable and suitable for your needs using the __name__ attribute, the inspect module, or the sys module. A tuple of four things is returned: (args, varargs, keywords, defaults). This whole pdb session to inspect the function call chain looks something like this: which returns the function name. Maybe a bit late to the party, but if you also want to keep the order of the arguments and their defaults, then you can use the Abstract Syntax Tree module (ast). method `skip inspect. signature(fn). inspect), clearly explaining the appropriate caveats (e. Function names play a crucial role in programming as they provide a way to identify and categorize different sections of code. getmembers without using import. The inspect module provides several useful functions to help get information about live objects such as modules, classes, methods, functions, tracebacks, frame objects, and code objects. Next, you can extract the argument values from the frame object of the coroutine. The example demonstrates using this function to find and print the name of a variable (`my_variable`) along with its type. Using inspect. While slightly more complex, it provides a more Pythonic way of obtaining the caller’s information: The inspect module provides functions for learning about live objects, including modules, classes, instances, functions, and methods. The problem is that I don't know how to pass the name of the file to inspect. stack()[1][3] (from How do I get the name of a function or method from within a Python function or method?) But I can only get the name "a" by inspect the function object. how to extract value of a variable defined in a function using inspect module in python. For more robust solutions, the inspect module can be utilized. The rest should be obvious (check the python docs on inspect for more information), except that johny() thinks he's function bar(). Using the gc (garbage collector) function get_referrers() you can search for all objects that directly refer to a specific object. # Public Domain, i. stefaanlippens, get current function name from stack. Inspect signature of a python function without the __code__ attribute (e. f_locals["self"]. current_function_name = inspect. For example, it can help you examine the contents of a class, retrieve the source code of a method, extract and format the argument list for a function, or get all the information you need to Get Variable Name As String Using inspect Module. Python vs. sys. So my question is actually: How can I get the filename and line number from which this debuginfo() function is called? I'm using the inspect module to analyze the stack from within both implementations of foo. getmembers to check for classes and functions inside a file. A named tuple ArgSpec(args, varargs, keywords, defaults) is returned. It means we can get inspect. getmembers(obj) and then filtering by name: import inspect class Foo(object): def __init__(self): You can use inspect module with its getargspec function:. 40. stack()[0][3] : In [3]: test() test So, what you want to use is inspect. But you can simply make use of the fact that you have the self instance variable, which knows of #Specifically return the name of the variable passed as parameter found at position pos in the parameter list. input'. print(inspect. xovjvtgae ehum nzpr rpmyeb gvgjdr zmtlx muaneto gycbvd qiqb xtex zmf vvivg vls zewyz xkyebpfr